Sajjad.Aghapour
جمعه 09 مرداد 1388, 21:05 عصر
سلام دوستان.کسی در این مورد می تونه کمک کنه:
Queue<Device> qList = new Queue<Device>();
Device dName = new Device();
dName.Name = "Mobile";
qList.Enqueue(dName);
XmlSerializer serialize = new XmlSerializer(typeof(Queue<Device>));
using (FileStream stream = new FileStream("lfc.xml", FileMode.Create, FileAccess.Write, FileShare.None))
{
serialize.Serialize(stream, qList);
}
یا
QueueqList = new Queue();
Device dName = new Device();
dName.Name = "Mobile";
qList.Enqueue(dName);
XmlSerializer serialize = new XmlSerializer(typeof(Queue));
using (FileStream stream = new FileStream("lfc.xml", FileMode.Create, FileAccess.Write, FileShare.None))
{
serialize.Serialize(stream, qList);
}
Queue<Device> qList = new Queue<Device>();
Device dName = new Device();
dName.Name = "Mobile";
qList.Enqueue(dName);
XmlSerializer serialize = new XmlSerializer(typeof(Queue<Device>));
using (FileStream stream = new FileStream("lfc.xml", FileMode.Create, FileAccess.Write, FileShare.None))
{
serialize.Serialize(stream, qList);
}
یا
QueueqList = new Queue();
Device dName = new Device();
dName.Name = "Mobile";
qList.Enqueue(dName);
XmlSerializer serialize = new XmlSerializer(typeof(Queue));
using (FileStream stream = new FileStream("lfc.xml", FileMode.Create, FileAccess.Write, FileShare.None))
{
serialize.Serialize(stream, qList);
}