msafvati
یک شنبه 26 مهر 1388, 19:29 عصر
با سلام خدمت دوستان
منم در حین کار با آژاکس و PHP با مشکل بر خورد کردم از دوستان خواهش می کنم که من رو راهنمایی کنند
با تشکر
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Untitled Document</title>
<script type="text/javascript">
function GetXmlHttpObject()
{
var xmlHttp=null;
try
{
// Firefox, Opera 8.0+, Safari
xmlHttp=new XMLHttpRequest();
}
catch (e)
{
//Internet Explorer
try
{
xmlHttp=new ActiveXObject("Msxml2.XMLHTTP");
}
catch (e)
{
xmlHttp=new ActiveXObject("Microsoft.XMLHTTP");
}
}
return xmlHttp;
}
function checkUser()
{
xmlHttp=GetXmlHttpObject();
if (xmlHttp==null)
{
alert ("Browser does not support HTTP Request");
return;
}
url='http://127.0.0.1/mas/index.php?user='+document.getElementById('user').v alue;
//alert(url);
xmlHttp.onreadystatechange=stateChanged;
xmlHttp.open("GET",url,true);
xmlHttp.send(null);
}
function stateChanged()
{
if (xmlHttp.readyState==4 || xmlHttp.readyState=="complete")
{
if (xmlHttp.responseText==1)
{
document.getElementById("user").style.border="1px solid #FF0000";
}
else{
document.getElementById("user").style.border="1px solid #00CC00";
}
}
}
</script>
</head>
<body>
<form action="http://127.0.0.1/mas/index.php" method="get">
<table width="300" border="0">
<tr>
<td><label for="name">name </label></td>
<td><input type="text" id="name" /></td>
<td> </td>
</tr>
<tr>
<td><label for="user">user </label></td>
<td><input type="text" id="user" /></td>
<td style="text-align:left"><input type="button" value="check" onclick="checkUser()"/></td>
</tr>
<tr>
<td><label for="pass">password</label></td>
<td><input type="password" id="pass" /></td>
<td> </td>
</tr>
<tr>
<td></td>
<td colspan="2"><input type="submit" id="send" /></td>
</tr>
</table>
</form>
</body>
</html>
PHP:
<?php
$con=mysql_connect('127.0.0.1','root','root');
if($con){
echo "Connection Successfuly \n";
}
$db=mysql_select_db('Ajax',$con);
$sql="SELECT * FROM `users` WHERE `user` ='".$_GET['user']."'";
$r=mysql_query($sql);
$result=mysql_num_rows($r);
echo( $result);
?>
منم در حین کار با آژاکس و PHP با مشکل بر خورد کردم از دوستان خواهش می کنم که من رو راهنمایی کنند
با تشکر
<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
<html xmlns="http://www.w3.org/1999/xhtml">
<head>
<meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
<title>Untitled Document</title>
<script type="text/javascript">
function GetXmlHttpObject()
{
var xmlHttp=null;
try
{
// Firefox, Opera 8.0+, Safari
xmlHttp=new XMLHttpRequest();
}
catch (e)
{
//Internet Explorer
try
{
xmlHttp=new ActiveXObject("Msxml2.XMLHTTP");
}
catch (e)
{
xmlHttp=new ActiveXObject("Microsoft.XMLHTTP");
}
}
return xmlHttp;
}
function checkUser()
{
xmlHttp=GetXmlHttpObject();
if (xmlHttp==null)
{
alert ("Browser does not support HTTP Request");
return;
}
url='http://127.0.0.1/mas/index.php?user='+document.getElementById('user').v alue;
//alert(url);
xmlHttp.onreadystatechange=stateChanged;
xmlHttp.open("GET",url,true);
xmlHttp.send(null);
}
function stateChanged()
{
if (xmlHttp.readyState==4 || xmlHttp.readyState=="complete")
{
if (xmlHttp.responseText==1)
{
document.getElementById("user").style.border="1px solid #FF0000";
}
else{
document.getElementById("user").style.border="1px solid #00CC00";
}
}
}
</script>
</head>
<body>
<form action="http://127.0.0.1/mas/index.php" method="get">
<table width="300" border="0">
<tr>
<td><label for="name">name </label></td>
<td><input type="text" id="name" /></td>
<td> </td>
</tr>
<tr>
<td><label for="user">user </label></td>
<td><input type="text" id="user" /></td>
<td style="text-align:left"><input type="button" value="check" onclick="checkUser()"/></td>
</tr>
<tr>
<td><label for="pass">password</label></td>
<td><input type="password" id="pass" /></td>
<td> </td>
</tr>
<tr>
<td></td>
<td colspan="2"><input type="submit" id="send" /></td>
</tr>
</table>
</form>
</body>
</html>
PHP:
<?php
$con=mysql_connect('127.0.0.1','root','root');
if($con){
echo "Connection Successfuly \n";
}
$db=mysql_select_db('Ajax',$con);
$sql="SELECT * FROM `users` WHERE `user` ='".$_GET['user']."'";
$r=mysql_query($sql);
$result=mysql_num_rows($r);
echo( $result);
?>