alicomputer
یک شنبه 15 اسفند 1389, 14:09 عصر
In this article you will learn how to insert an image from database SQL Server
Inserting an image in database
Creating a table in SQL Server.
Table name student and database name master.
use master
go
create table student
(
name varchar(20),
rollno int,
photo image
);
go
select * from student;
go
Now come to the front end window forms application in VB.NET.
Taking two level, two textbox and three button and one picture box and opendialog control on the form
Table has created in SQL Server..
Now double click on the button named browse and add the following code in c#.
private void button1_Click(object sender, EventArgs e)
{
openFileDialog1.Filter = "Image Files|*.gif;*.jpg;*.png;*.bmp";
openFileDialog1.ShowDialog();
pictureBox1.Image = Image.FromFile(openFileDialog1.FileName);
}
code in visual Basic.
private void button1_Click(object sender, EventArgs e)
{
openFileDialog1.Filter = "Image Files|*.gif;*.jpg;*.png;*.bmp";
openFileDialog1.ShowDialog();
pictureBox1.Image = Image.FromFile(openFileDialog1.FileName);
}
Now double click on the button save and add the following c# code.
private void button2_Click(object sender, EventArgs e)
{
string str = "Data Source=.;uid=sa;pwd=wintellect;database=master";
SqlConnection con = new SqlConnection(str);
con.Open();
string sql = "INSERT INTO student VALUES(@rollno,@name,@photo)";
SqlCommand cmd = new SqlCommand(sql, con);
cmd.Parameters.AddWithValue("@rollno", textBox1.Text);
cmd.Parameters.AddWithValue("@name", textBox2.Text);
MemoryStream ms = new MemoryStream();
pictureBox1.Image.Save(ms, pictureBox1.Image.RawFormat);
byte[] data = ms.GetBuffer();
SqlParameter p = new SqlParameter("@photo", SqlDbType.Image);
p.Value = data;
cmd.Parameters.Add(p);
cmd.ExecuteNonQuery();
MessageBox.Show("record has been saved","Save", MessageBoxButtons .OK);
con.Close();
}
code in visual Basic.
Private Sub button2_Click(ByVal sender As Object, ByVal e As EventArgs) Dim str As String = "Data Source=.;uid=sa;pwd=wintellect;database=master"
Dim con As New SqlConnection(str)
con.Open()
Dim sql As String = "INSERT INTO student VALUES(@rollno,@name,@photo)"
Dim cmd As New SqlCommand(sql, con)
cmd.Parameters.AddWithValue("@rollno", textBox1.Text)
cmd.Parameters.AddWithValue("@name", textBox2.Text)
Dim ms As New MemoryStream()
pictureBox1.Image.Save(ms, pictureBox1.Image.RawFormat)
Dim data As Byte() = ms.GetBuffer()
Dim p As New SqlParameter("@photo", SqlDbType.Image)
p.Value = data
cmd.Parameters.Add(p)
cmd.ExecuteNonQuery()
MessageBox.Show("record has been saved", "Save", MessageBoxButtons.OK)
con.Close()
End Sub
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Inserting an image in database
Creating a table in SQL Server.
Table name student and database name master.
use master
go
create table student
(
name varchar(20),
rollno int,
photo image
);
go
select * from student;
go
Now come to the front end window forms application in VB.NET.
Taking two level, two textbox and three button and one picture box and opendialog control on the form
Table has created in SQL Server..
Now double click on the button named browse and add the following code in c#.
private void button1_Click(object sender, EventArgs e)
{
openFileDialog1.Filter = "Image Files|*.gif;*.jpg;*.png;*.bmp";
openFileDialog1.ShowDialog();
pictureBox1.Image = Image.FromFile(openFileDialog1.FileName);
}
code in visual Basic.
private void button1_Click(object sender, EventArgs e)
{
openFileDialog1.Filter = "Image Files|*.gif;*.jpg;*.png;*.bmp";
openFileDialog1.ShowDialog();
pictureBox1.Image = Image.FromFile(openFileDialog1.FileName);
}
Now double click on the button save and add the following c# code.
private void button2_Click(object sender, EventArgs e)
{
string str = "Data Source=.;uid=sa;pwd=wintellect;database=master";
SqlConnection con = new SqlConnection(str);
con.Open();
string sql = "INSERT INTO student VALUES(@rollno,@name,@photo)";
SqlCommand cmd = new SqlCommand(sql, con);
cmd.Parameters.AddWithValue("@rollno", textBox1.Text);
cmd.Parameters.AddWithValue("@name", textBox2.Text);
MemoryStream ms = new MemoryStream();
pictureBox1.Image.Save(ms, pictureBox1.Image.RawFormat);
byte[] data = ms.GetBuffer();
SqlParameter p = new SqlParameter("@photo", SqlDbType.Image);
p.Value = data;
cmd.Parameters.Add(p);
cmd.ExecuteNonQuery();
MessageBox.Show("record has been saved","Save", MessageBoxButtons .OK);
con.Close();
}
code in visual Basic.
Private Sub button2_Click(ByVal sender As Object, ByVal e As EventArgs) Dim str As String = "Data Source=.;uid=sa;pwd=wintellect;database=master"
Dim con As New SqlConnection(str)
con.Open()
Dim sql As String = "INSERT INTO student VALUES(@rollno,@name,@photo)"
Dim cmd As New SqlCommand(sql, con)
cmd.Parameters.AddWithValue("@rollno", textBox1.Text)
cmd.Parameters.AddWithValue("@name", textBox2.Text)
Dim ms As New MemoryStream()
pictureBox1.Image.Save(ms, pictureBox1.Image.RawFormat)
Dim data As Byte() = ms.GetBuffer()
Dim p As New SqlParameter("@photo", SqlDbType.Image)
p.Value = data
cmd.Parameters.Add(p)
cmd.ExecuteNonQuery()
MessageBox.Show("record has been saved", "Save", MessageBoxButtons.OK)
con.Close()
End Sub
این هم لینک سایت اصلی کلیک کنید
این هم لینک سایت اصلی کلیک (http://www.vbdotnetheaven.com/UploadFile/rohatash/3876/)کنید