p30rex
سه شنبه 31 اردیبهشت 1392, 16:43 عصر
سلام
اسکریپت login سایتم اینجوریه:
function sec_session_start() {
$session_name = 'sec_session_id'; // Set a custom session name
$secure = false; // Set to true if using https.
$httponly = true; // This stops javascript being able to access the session id.
ini_set('session.use_only_cookies', 1); // Forces sessions to only use cookies.
$cookieParams = session_get_cookie_params(); // Gets current cookies params.
session_set_cookie_params($cookieParams["lifetime"], $cookieParams["path"], $cookieParams["domain"], $secure, $httponly);
session_name($session_name); // Sets the session name to the one set above.
session_start(); // Start the php session
session_regenerate_id(true); // regenerated the session, delete the old one.
}
function login($email, $password, $mysqli) {
// Using prepared Statements means that SQL injection is not possible.
if ($stmt = $mysqli->prepare("SELECT id, username, password, salt FROM members WHERE email = ? LIMIT 1")) {
$stmt->bind_param('s', $email); // Bind "$email" to parameter.
$stmt->execute(); // Execute the prepared query.
$stmt->store_result();
$stmt->bind_result($user_id, $username, $db_password, $salt); // get variables from result.
$stmt->fetch();
$password = hash('sha512', $password.$salt); // hash the password with the unique salt.
if($stmt->num_rows == 1) { // If the user exists
// We check if the account is locked from too many login attempts
if(checkbrute($user_id, $mysqli) == true) {
// Account is locked
// Send an email to user saying their account is locked
return false;
} else {
if($db_password == $password) { // Check if the password in the database matches the password the user submitted.
// Password is correct!
$user_browser = $_SERVER['HTTP_USER_AGENT']; // Get the user-agent string of the user.
$user_id = preg_replace("/[^0-9]+/", "", $user_id); // XSS protection as we might print this value
$_SESSION['user_id'] = $user_id;
$username = preg_replace("/[^a-zA-Z0-9_\-]+/", "", $username); // XSS protection as we might print this value
$_SESSION['username'] = $username;
$_SESSION['login_string'] = hash('sha512', $password.$user_browser);
// Login successful.
return true;
} else {
// Password is not correct
// We record this attempt in the database
$now = time();
$mysqli->query("INSERT INTO login_attempts (user_id, time) VALUES ('$user_id', '$now')");
return false;
}
}
} else {
// No user exists.
return false;
}
}
}
حالا من میخام user_id کسی که login شده رو داشته باشم
چرا این کد جواب نمیده؟:
seesion_start();
echo $_session['user_id'];
این ارور رو میده:
Notice: Undefined index: user_id in C:\wamp\www\sch\admin\index.php on line 4
اسکریپت login سایتم اینجوریه:
function sec_session_start() {
$session_name = 'sec_session_id'; // Set a custom session name
$secure = false; // Set to true if using https.
$httponly = true; // This stops javascript being able to access the session id.
ini_set('session.use_only_cookies', 1); // Forces sessions to only use cookies.
$cookieParams = session_get_cookie_params(); // Gets current cookies params.
session_set_cookie_params($cookieParams["lifetime"], $cookieParams["path"], $cookieParams["domain"], $secure, $httponly);
session_name($session_name); // Sets the session name to the one set above.
session_start(); // Start the php session
session_regenerate_id(true); // regenerated the session, delete the old one.
}
function login($email, $password, $mysqli) {
// Using prepared Statements means that SQL injection is not possible.
if ($stmt = $mysqli->prepare("SELECT id, username, password, salt FROM members WHERE email = ? LIMIT 1")) {
$stmt->bind_param('s', $email); // Bind "$email" to parameter.
$stmt->execute(); // Execute the prepared query.
$stmt->store_result();
$stmt->bind_result($user_id, $username, $db_password, $salt); // get variables from result.
$stmt->fetch();
$password = hash('sha512', $password.$salt); // hash the password with the unique salt.
if($stmt->num_rows == 1) { // If the user exists
// We check if the account is locked from too many login attempts
if(checkbrute($user_id, $mysqli) == true) {
// Account is locked
// Send an email to user saying their account is locked
return false;
} else {
if($db_password == $password) { // Check if the password in the database matches the password the user submitted.
// Password is correct!
$user_browser = $_SERVER['HTTP_USER_AGENT']; // Get the user-agent string of the user.
$user_id = preg_replace("/[^0-9]+/", "", $user_id); // XSS protection as we might print this value
$_SESSION['user_id'] = $user_id;
$username = preg_replace("/[^a-zA-Z0-9_\-]+/", "", $username); // XSS protection as we might print this value
$_SESSION['username'] = $username;
$_SESSION['login_string'] = hash('sha512', $password.$user_browser);
// Login successful.
return true;
} else {
// Password is not correct
// We record this attempt in the database
$now = time();
$mysqli->query("INSERT INTO login_attempts (user_id, time) VALUES ('$user_id', '$now')");
return false;
}
}
} else {
// No user exists.
return false;
}
}
}
حالا من میخام user_id کسی که login شده رو داشته باشم
چرا این کد جواب نمیده؟:
seesion_start();
echo $_session['user_id'];
این ارور رو میده:
Notice: Undefined index: user_id in C:\wamp\www\sch\admin\index.php on line 4