مخرب و سازنده _ constructor & destructor

[topcoder]

#include <iostream>
using namespace std;
class foo
{
private:
int num,den;

public:
foo() : num(0) , den(0)
{
cout<<"constructor runs !"<<endl;
}
~foo()
{
cout<<"destructor runs !"<<endl;
}
foo(const foo& r) : num(r.num) , den(r.num)
{
cout<<"copy constructor runs !"<<endl;
}
foo& operator =(const foo& r)
{
cout<<"assingment runs !"<<endl;
return *this;

}
};
foo all(foo x)
{
cout<<"in function"<<endl;
return x;
}
int main()
{
foo a;

foo s;

s=all(a);

cout<<"tst end"<<endl;

cout<<"---------------"<<endl;
return 0;
}


دوستان کسی میدونه مخرب برای بار دوم چرا صدا زده میشه ؟
بعد از = یک بار مخرب صدا زده میشه هرچی فکر میکنم دلیلی براش پیدا نمیکنم :-|

[manij_mhm]

خروجی کد شما به صورت زیر است:
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دو خط اول که واضحه!
خط سوم برای کپی پارامتر ورودی تابع است. خط 4 برای اجرای تابع و خط 5 برای ایجاد یه متغیر برای خروجی برنامه است. قبل از خارج شدن از تابع، پارامتر ورودی حذف میشه(خط 6)!
در ادامه مقدار خروجی به s داده میشه (7) و خروجی تابع پاک میشه(خط 8 که مد نظرتونه)!! بعد هم پایان برنامه و حذف دو متغیر s,a

[manij_mhm]

104627

تصویر در بالا اضافه نشده بود! اینم خروجی برنامه شما

[topcoder]

مرسی ممنون بابته پاسختون :)
حالا کد زیر رو در نظر بگیرین اگر تو مین برنامه جایگزینش کنین

foo s = all(a);
اونوقت تو این چرا شی نمیسازه که بخواد بعد پاکش کنه ؟

[manij_mhm]

کدی که شما نوشتید باعث میشه که دیگه مقدار بازگشتی درون متغیر جدیدی قرار نگیره!! یعنی دیگه عملگر مساوی کار نمی کنه که یه شی جدید ساخته بشه و اون شی جدید به s تخصیص داده بشه! دلیلشم نوع S هست که در اینجا صراحتا اورده شده.