tanha2007
سه شنبه 06 شهریور 1386, 07:36 صبح
تشکر از همه، ولی نمیدانم چرا اطلاعات رانمایش نمیدهد:
<HTML>
<BODY>
<FORM Action="SearchInSide.php" Method="POST">
<div align="center">
<table border="0" cellpadding="0" cellspacing="0">
<tr>
<td bordercolor="#000000">
<p align="center">
<select name="metode" size="1">
<option value="name">Name</option>
<option value="telephone">Telephone</option>
<option value="birthday">Birthday</option>
</select> <input type="text" name="search" size="25"> <br>
Search database: <input type="submit" value="Go!!" name="Go"></p>
</td>
</tr>
</table>
</div>
</form>
<center>
<table border="1" cellpadding="5" cellspacing="0" bordercolor="#000000">
<tr>
<td width="60"><b>ID</b></td>
<td width="100"><b>Name</b></td>
<td width="70"><b>Telephone</b></td>
<td width="150"><b>Birthday</b></td>
</tr>
<?php
$hostname = "localhost"; // The Thinkhost DB server.
$username = "root"; // The username you created for this database.
$password = ""; // The password you created for the username.
$usertable = "details"; // The name of the table you made.
$dbName = "example"; // This is the name of the database you made.
MYSQL_CONNECT($hostname, $username, $password) OR DIE("DB connection unavailable");
@mysql_select_db( "$dbName") or die( "Unable to select database");
?>
<?php
//error message (not found message)begins
$XX = "No Record Found, to search again please try again";
//query details table begins
$query = mysql_query("SELECT * FROM details WHERE '$_POST[metode]' LIKE '$_POST[search]'% LIMIT 0, 50");
while ($row = @mysql_fetch_array($query))
{
$variable1=$row["id"];
$variable2=$row["name"];
$variable3=$row["telephone"];
$variable4=$row["birthday"];
//table layout for results
print ("<tr>");
print ("<td>$variable1</td>");
print ("<td>$variable2</td>");
print ("<td>$variable3</td>");
print ("<td>$variable4</td>");
print ("</tr>");
}
//below this is the function for no record!!
if (!$variable1)
{
print ("$XX");
}
//end
?>
</table>
</center>
</BODY>
</HTML>